No, the digits of pi are not truly random, therefore you can win money playing against a supercomputer that can calculate the digits of pi far beyond what we are currently capable of doing. This computer selects a position in the decimal expansion of pi -- say, at 10^100.
Your job is to guess what the next digit or digit sequence is. Specifically, you have one dollar to bet. A bet on the next digit, if correct, returns 10 times the amount bet; a bet on the next two digits returns 100 times the amount bet, and so on. (The dollar may be divided in any fashion, so we could bet 1/3 or 1/10000 of a dollar.) You may place bets in any combination. The computer will tell you the position number, let you examine the digits up to that point, and calculate statistics for you.
It is easy to set up strategies that might win, if the supercomputer doesn't know your strategy. For example, "Always bet on 7" might win, if you are lucky. Also, it is easy to set up bets that will always return a dollar. For example, if you bet a penny on every two-digit sequence, you are sure to win back your dollar. Also, there are strategies that might be winning, but we can't prove it. For example, it may be that a certain sequence of digits never occurs in pi, but we have no way of proving this.
The problem is to find a strategy that you can prove will always win back more than a dollar.
The assumption that the position is beyond the reach of calculation means that we must rely on general facts we know about the sequence of digits of pi, which is practically nil. But it is not completely nil, and the challenge is to find a strategy that will always win money.
A theorem of Mahler (1953) states that for all integers p, q > 1,
This says that pi cannot have a rational approximation that is extremely tight.
- digits, treated as a fraction with denominator 10^N, satisfies
- |pi - p / 10^N| < 10^(-42 N)
which contradicts Mahler's theorem.
So, I split my dollar into 10^(41N) - 1 equal parts, and bet on each of the sequences of 41N digits, except the one with all zeroes. One of the bets is sure to win, so my total profit is about 10(^-41N) of a dollar!
This strategy can be improved a number of ways, such as looking for other repeating patterns, or improvements to the bound of 42 -- but the earnings are so pathetic, it hardly seems worth the effort.